JEE MAIN - Physics (2019 - 11th January Morning Slot - No. 28)
A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. considering only translational and rotational modes, the total internal energy of the system is :
12 RT
20 RT
4 RT
15 RT
Explicació
U $$ = {{{f_1}} \over 2}{n_1}RT + {{{f_2}} \over 2}{n_2}RT$$
$$ = {5 \over 2}\left( {3RT} \right) + {3 \over 2} \times 5RT$$
U $$ = 15RT$$
$$ = {5 \over 2}\left( {3RT} \right) + {3 \over 2} \times 5RT$$
U $$ = 15RT$$